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X^2+11X-222=0
a = 1; b = 11; c = -222;
Δ = b2-4ac
Δ = 112-4·1·(-222)
Δ = 1009
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-\sqrt{1009}}{2*1}=\frac{-11-\sqrt{1009}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+\sqrt{1009}}{2*1}=\frac{-11+\sqrt{1009}}{2} $
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